Solve for x natural log of e^x=3

$\ln (e^{x}) = 3$

Expand $\ln (e^{x})$ .

Expand $\ln (e^{x})$ by moving $x$ outside the logarithm.

$x \ln (e)$

The natural logarithm of $e$ is $1$ .

$x \cdot 1$

Multiply $x$ by $1$ .

$x$

$x$

The expanded equation is $x = 3$ .

$x = 3$

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