Solve for x square root of 2x-6<4

$\sqrt{2 x - 6} < 4$

Step 1

To remove the radical on the left side of the inequality, square both sides of the inequality.

${\sqrt{2 x - 6}}^{2} < 4^{2}$

Step 2

Simplify each side of the inequality.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2 x - 6}$ as ${(2 x - 6)}^{\frac{1}{2}}$ .

${({(2 x - 6)}^{\frac{1}{2}})}^{2} < 4^{2}$

Simplify the left side.

Simplify ${({(2 x - 6)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(2 x - 6)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(2 x - 6)}^{\frac{1}{2} \cdot 2} < 4^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(2 x - 6)}^{\frac{1}{2} \cdot 2} < 4^{2}$

Rewrite the expression.

${(2 x - 6)}^{1} < 4^{2}$

Simplify.

$2 x - 6 < 4^{2}$

Simplify the right side.

Raise $4$ to the power of $2$ .

$2 x - 6 < 16$

Step 3

Solve for $x$ .

Move all terms not containing $x$ to the right side of the inequality.

Add $6$ to both sides of the inequality.

$2 x < 16 + 6$

Add $16$ and $6$ .

$2 x < 22$

Divide each term in $2 x < 22$ by $2$ and simplify.

Divide each term in $2 x < 22$ by $2$ .

$\frac{2 x}{2} < \frac{22}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} < \frac{22}{2}$

Divide $x$ by $1$ .

$x < \frac{22}{2}$

Simplify the right side.

Divide $22$ by $2$ .

$x < 11$

Step 4

Find the domain of $\sqrt{2 (x - 3)} - 4$ .

Set the radicand in $\sqrt{2 (x - 3)}$ greater than or equal to $0$ to find where the expression is defined.

$2 (x - 3) \geq 0$

Solve for $x$ .

Divide each term in $2 (x - 3) \geq 0$ by $2$ and simplify.

Divide each term in $2 (x - 3) \geq 0$ by $2$ .

$\frac{2 (x - 3)}{2} \geq \frac{0}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 (x - 3)}{2} \geq \frac{0}{2}$

Divide $x - 3$ by $1$ .

$x - 3 \geq \frac{0}{2}$

Simplify the right side.

Divide $0$ by $2$ .

$x - 3 \geq 0$

Add $3$ to both sides of the inequality.

$x \geq 3$

The domain is all values of $x$ that make the expression defined.

$[3, \infty)$

Step 5

Use each root to create test intervals.

$x < 3$

$3 < x < 11$

$x > 11$

Step 6

Choose a test value from each interval and plug this value into the original inequality to determine which intervals satisfy the inequality.

Test a value on the interval $x < 3$ to see if it makes the inequality true.

Choose a value on the interval $x < 3$ and see if this value makes the original inequality true.

$x = 0$

Replace $x$ with $0$ in the original inequality.

$\sqrt{2 (0) - 6} < 4$

The left side is not equal to the right side, which means that the given statement is false.

False

Test a value on the interval $3 < x < 11$ to see if it makes the inequality true.

Choose a value on the interval $3 < x < 11$ and see if this value makes the original inequality true.

$x = 7$

Replace $x$ with $7$ in the original inequality.

$\sqrt{2 (7) - 6} < 4$

The left side $2.82842712$ is less than the right side $4$ , which means that the given statement is always true.

True

Test a value on the interval $x > 11$ to see if it makes the inequality true.

Choose a value on the interval $x > 11$ and see if this value makes the original inequality true.

$x = 14$

Replace $x$ with $14$ in the original inequality.

$\sqrt{2 (14) - 6} < 4$

The left side $4.69041575$ is not less than the right side $4$ , which means that the given statement is false.

False

Compare the intervals to determine which ones satisfy the original inequality.

$x < 3$ False

$3 < x < 11$ True

$x > 11$ False

$x < 3$ False

$3 < x < 11$ True

$x > 11$ False

Step 7

The solution consists of all of the true intervals.

$3 < x < 11$

Step 8

The result can be shown in multiple forms.

Inequality Form:

$3 < x < 11$

Interval Notation:

$(3, 11)$

Step 9

Solve for x square root of 2x-6<4

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