Solve for x (x-1)^3-5=0

${(x - 1)}^{3} - 5 = 0$

Add $5$ to both sides of the equation.

${(x - 1)}^{3} = 5$

Take the cube root of both sides of the equation to eliminate the exponent on the left side.

$x - 1 = \sqrt[3]{5}$

Add $1$ to both sides of the equation.

$x = \sqrt[3]{5} + 1$

The result can be shown in multiple forms.

Exact Form:

$x = \sqrt[3]{5} + 1$

Decimal Form:

$x = 2.70997594 \dots$