Solve for x (x-10)^2-1=0

${(x - 10)}^{2} - 1 = 0$

Add $1$ to both sides of the equation.

${(x - 10)}^{2} = 1$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x - 10 = \pm \sqrt{1}$

Any root of $1$ is $1$ .

$x - 10 = \pm 1$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x - 10 = 1$

Move all terms not containing $x$ to the right side of the equation.

Add $10$ to both sides of the equation.

$x = 1 + 10$

Add $1$ and $10$ .

$x = 11$

Next, use the negative value of the $\pm$ to find the second solution.

$x - 10 = - 1$

Move all terms not containing $x$ to the right side of the equation.

Add $10$ to both sides of the equation.

$x = - 1 + 10$

Add $- 1$ and $10$ .

$x = 9$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 11, 9$