Solve for x x^2+2x-4=2x

$x^{2} + 2 x - 4 = 2 x$

Step 1

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$x^{2} + 2 x - 4 - 2 x = 0$

Combine the opposite terms in $x^{2} + 2 x - 4 - 2 x$ .

Subtract $2 x$ from $2 x$ .

$x^{2} + 0 - 4 = 0$

Add $x^{2}$ and $0$ .

$x^{2} - 4 = 0$

Step 2

Add $4$ to both sides of the equation.

$x^{2} = 4$

Step 3

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{4}$

Step 4

Simplify $\pm \sqrt{4}$ .

Rewrite $4$ as $2^{2}$ .

$x = \pm \sqrt{2^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 2$

Step 5

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = 2$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 2$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 2, - 2$