Solve for x x^2-6=(5x)/2

$x^{2} - 6 = \frac{5 x}{2}$

Multiply both sides by $2$ .

$(x^{2} - 6) \cdot 2 = \frac{5 x}{2} \cdot 2$

Simplify.

Simplify the left side.

Simplify $(x^{2} - 6) \cdot 2$ .

Apply the distributive property.

$x^{2} \cdot 2 - 6 \cdot 2 = \frac{5 x}{2} \cdot 2$

Simplify the expression.

Move $2$ to the left of $x^{2}$ .

$2 \cdot x^{2} - 6 \cdot 2 = \frac{5 x}{2} \cdot 2$

Multiply $- 6$ by $2$ .

$2 x^{2} - 12 = \frac{5 x}{2} \cdot 2$

Simplify the right side.

Cancel the common factor of $2$ .

Cancel the common factor.

$2 x^{2} - 12 = \frac{5 x}{2} \cdot 2$

Rewrite the expression.

$2 x^{2} - 12 = 5 x$

Solve for $x$ .

Subtract $5 x$ from both sides of the equation.

$2 x^{2} - 12 - 5 x = 0$

Factor by grouping.

Reorder terms.

$2 x^{2} - 5 x - 12 = 0$

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 2 \cdot - 12 = - 24$ and whose sum is $b = - 5$ .

Factor $- 5$ out of $- 5 x$ .

$2 x^{2} - 5 x - 12 = 0$

Rewrite $- 5$ as $3$ plus $- 8$

$2 x^{2} + (3 - 8) x - 12 = 0$

Apply the distributive property.

$2 x^{2} + 3 x - 8 x - 12 = 0$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(2 x^{2} + 3 x) - 8 x - 12 = 0$

Factor out the greatest common factor (GCF) from each group.

$x (2 x + 3) - 4 (2 x + 3) = 0$

Factor the polynomial by factoring out the greatest common factor, $2 x + 3$ .

$(2 x + 3) (x - 4) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$2 x + 3 = 0$

$x - 4 = 0$

Set $2 x + 3$ equal to $0$ and solve for $x$ .

Set $2 x + 3$ equal to $0$ .

$2 x + 3 = 0$

Solve $2 x + 3 = 0$ for $x$ .

Subtract $3$ from both sides of the equation.

$2 x = - 3$

Divide each term in $2 x = - 3$ by $2$ and simplify.

Divide each term in $2 x = - 3$ by $2$ .

$\frac{2 x}{2} = \frac{- 3}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 3}{2}$

Divide $x$ by $1$ .

$x = \frac{- 3}{2}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{3}{2}$

Set $x - 4$ equal to $0$ and solve for $x$ .

Set $x - 4$ equal to $0$ .

$x - 4 = 0$

Add $4$ to both sides of the equation.

$x = 4$

The final solution is all the values that make $(2 x + 3) (x - 4) = 0$ true.

$x = - \frac{3}{2}, 4$

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{3}{2}, 4$

Decimal Form:

$x = - 1.5, 4$

Mixed Number Form:

$x = - 1 \frac{1}{2}, 4$

Solve for x x^2-6=(5x)/2

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