Solve for x x+ax=b

$x + a x = b$

Factor $x$ out of $x + a x$ .

Raise $x$ to the power of $1$ .

$x + a x = b$

Factor $x$ out of $x^{1}$ .

$x \cdot 1 + a x = b$

Factor $x$ out of $a x$ .

$x \cdot 1 + x a = b$

Factor $x$ out of $x \cdot 1 + x a$ .

$x (1 + a) = b$

Divide each term in $x (1 + a) = b$ by $1 + a$ and simplify.

Divide each term in $x (1 + a) = b$ by $1 + a$ .

$\frac{x (1 + a)}{1 + a} = \frac{b}{1 + a}$

Simplify the left side.

Cancel the common factor of $1 + a$ .

Cancel the common factor.

$\frac{x (1 + a)}{1 + a} = \frac{b}{1 + a}$

Divide $x$ by $1$ .

$x = \frac{b}{1 + a}$