Solve for x xy+8=z+7

$x y + 8 = z + 7$

Step 1

Move all terms not containing $x$ to the right side of the equation.

Subtract $8$ from both sides of the equation.

$x y = z + 7 - 8$

Subtract $8$ from $7$ .

$x y = z - 1$

Step 2

Divide each term in $x y = z - 1$ by $y$ and simplify.

Divide each term in $x y = z - 1$ by $y$ .

$\frac{x y}{y} = \frac{z}{y} + \frac{- 1}{y}$

Simplify the left side.

Cancel the common factor of $y$ .

Cancel the common factor.

$\frac{x y}{y} = \frac{z}{y} + \frac{- 1}{y}$

Divide $x$ by $1$ .

$x = \frac{z}{y} + \frac{- 1}{y}$

Simplify the right side.

Move the negative in front of the fraction.

$x = \frac{z}{y} - \frac{1}{y}$