Solve for y 6y+2(y-4)=56

$6 y + 2 (y - 4) = 56$

Step 1

Simplify $6 y + 2 (y - 4)$ .

Simplify each term.

Apply the distributive property.

$6 y + 2 y + 2 \cdot - 4 = 56$

Multiply $2$ by $- 4$ .

$6 y + 2 y - 8 = 56$

Add $6 y$ and $2 y$ .

$8 y - 8 = 56$

Step 2

Move all terms not containing $y$ to the right side of the equation.

Add $8$ to both sides of the equation.

$8 y = 56 + 8$

Add $56$ and $8$ .

$8 y = 64$

Step 3

Divide each term in $8 y = 64$ by $8$ and simplify.

Divide each term in $8 y = 64$ by $8$ .

$\frac{8 y}{8} = \frac{64}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 y}{8} = \frac{64}{8}$

Divide $y$ by $1$ .

$y = \frac{64}{8}$

Simplify the right side.

Divide $64$ by $8$ .

$y = 8$