Solve for y x=2(2y-8)

$x = 2 (2 y - 8)$

Rewrite the equation as $2 (2 y - 8) = x$ .

$2 (2 y - 8) = x$

Divide each term in $2 (2 y - 8) = x$ by $2$ and simplify.

Divide each term in $2 (2 y - 8) = x$ by $2$ .

$\frac{2 (2 y - 8)}{2} = \frac{x}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 (2 y - 8)}{2} = \frac{x}{2}$

Divide $2 y - 8$ by $1$ .

$2 y - 8 = \frac{x}{2}$

Add $8$ to both sides of the equation.

$2 y = \frac{x}{2} + 8$

Divide each term in $2 y = \frac{x}{2} + 8$ by $2$ and simplify.

Divide each term in $2 y = \frac{x}{2} + 8$ by $2$ .

$\frac{2 y}{2} = \frac{\frac{x}{2}}{2} + \frac{8}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{\frac{x}{2}}{2} + \frac{8}{2}$

Divide $y$ by $1$ .

$y = \frac{\frac{x}{2}}{2} + \frac{8}{2}$

Simplify the right side.

Simplify each term.

Multiply the numerator by the reciprocal of the denominator.

$y = \frac{x}{2} \cdot \frac{1}{2} + \frac{8}{2}$

Multiply $\frac{x}{2} \cdot \frac{1}{2}$ .

Multiply $\frac{x}{2}$ by $\frac{1}{2}$ .

$y = \frac{x}{2 \cdot 2} + \frac{8}{2}$

Multiply $2$ by $2$ .

$y = \frac{x}{4} + \frac{8}{2}$

Divide $8$ by $2$ .

$y = \frac{x}{4} + 4$