Solve for y (y+1)/2=-2(y+1)

$\frac{y + 1}{2} = - 2 (y + 1)$

Multiply both sides by $2$ .

$\frac{y + 1}{2} \cdot 2 = - 2 (y + 1) \cdot 2$

Simplify.

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{y + 1}{2} \cdot 2 = - 2 (y + 1) \cdot 2$

Rewrite the expression.

$y + 1 = - 2 (y + 1) \cdot 2$

Simplify the right side.

Simplify $- 2 (y + 1) \cdot 2$ .

Apply the distributive property.

$y + 1 = (- 2 y - 2 \cdot 1) \cdot 2$

Multiply $- 2$ by $1$ .

$y + 1 = (- 2 y - 2) \cdot 2$

Apply the distributive property.

$y + 1 = - 2 y \cdot 2 - 2 \cdot 2$

Multiply.

Multiply $2$ by $- 2$ .

$y + 1 = - 4 y - 2 \cdot 2$

Multiply $- 2$ by $2$ .

$y + 1 = - 4 y - 4$

Solve for $y$ .

Move all terms containing $y$ to the left side of the equation.

Add $4 y$ to both sides of the equation.

$y + 1 + 4 y = - 4$

Add $y$ and $4 y$ .

$5 y + 1 = - 4$

Move all terms not containing $y$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$5 y = - 4 - 1$

Subtract $1$ from $- 4$ .

$5 y = - 5$

Divide each term in $5 y = - 5$ by $5$ and simplify.

Divide each term in $5 y = - 5$ by $5$ .

$\frac{5 y}{5} = \frac{- 5}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 y}{5} = \frac{- 5}{5}$

Divide $y$ by $1$ .

$y = \frac{- 5}{5}$

Simplify the right side.

Divide $- 5$ by $5$ .

$y = - 1$

Solve for y (y+1)/2=-2(y+1)

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