Solve for z 4-3z=9-6z+13

$4 - 3 z = 9 - 6 z + 13$

Step 1

Add $9$ and $13$ .

$4 - 3 z = - 6 z + 22$

Step 2

Move all terms containing $z$ to the left side of the equation.

Add $6 z$ to both sides of the equation.

$4 - 3 z + 6 z = 22$

Add $- 3 z$ and $6 z$ .

$4 + 3 z = 22$

Step 3

Move all terms not containing $z$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$3 z = 22 - 4$

Subtract $4$ from $22$ .

$3 z = 18$

Step 4

Divide each term in $3 z = 18$ by $3$ and simplify.

Divide each term in $3 z = 18$ by $3$ .

$\frac{3 z}{3} = \frac{18}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 z}{3} = \frac{18}{3}$

Divide $z$ by $1$ .

$z = \frac{18}{3}$

Simplify the right side.

Divide $18$ by $3$ .

$z = 6$