Solve the Inequality for a 3(3a-8)>-96

$3 (3 a - 8) > - 96$

Divide each term in $3 (3 a - 8) > - 96$ by $3$ and simplify.

Divide each term in $3 (3 a - 8) > - 96$ by $3$ .

$\frac{3 (3 a - 8)}{3} > \frac{- 96}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (3 a - 8)}{3} > \frac{- 96}{3}$

Divide $3 a - 8$ by $1$ .

$3 a - 8 > \frac{- 96}{3}$

Simplify the right side.

Divide $- 96$ by $3$ .

$3 a - 8 > - 32$

Move all terms not containing $a$ to the right side of the inequality.

Add $8$ to both sides of the inequality.

$3 a > - 32 + 8$

Add $- 32$ and $8$ .

$3 a > - 24$

Divide each term in $3 a > - 24$ by $3$ and simplify.

Divide each term in $3 a > - 24$ by $3$ .

$\frac{3 a}{3} > \frac{- 24}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 a}{3} > \frac{- 24}{3}$

Divide $a$ by $1$ .

$a > \frac{- 24}{3}$

Simplify the right side.

Divide $- 24$ by $3$ .

$a > - 8$

The result can be shown in multiple forms.

Inequality Form:

$a > - 8$

Interval Notation:

$(- 8, \infty)$