Solve the Inequality for b 7b-3<11

$7 b - 3 < 11$

Move all terms not containing $b$ to the right side of the inequality.

Add $3$ to both sides of the inequality.

$7 b < 11 + 3$

Add $11$ and $3$ .

$7 b < 14$

Divide each term in $7 b < 14$ by $7$ and simplify.

Divide each term in $7 b < 14$ by $7$ .

$\frac{7 b}{7} < \frac{14}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 b}{7} < \frac{14}{7}$

Divide $b$ by $1$ .

$b < \frac{14}{7}$

Simplify the right side.

Divide $14$ by $7$ .

$b < 2$

The result can be shown in multiple forms.

Inequality Form:

$b < 2$

Interval Notation:

$(- \infty, 2)$