Solve the Inequality for m 1+m/3<=6

$1 + \frac{m}{3} \leq 6$

Step 1

Move all terms not containing $m$ to the right side of the inequality.

Subtract $1$ from both sides of the inequality.

$\frac{m}{3} \leq 6 - 1$

Subtract $1$ from $6$ .

$\frac{m}{3} \leq 5$

Step 2

Multiply both sides by $3$ .

$\frac{m}{3} \cdot 3 \leq 5 \cdot 3$

Step 3

Simplify.

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{m}{3} \cdot 3 \leq 5 \cdot 3$

Rewrite the expression.

$m \leq 5 \cdot 3$

Simplify the right side.

Multiply $5$ by $3$ .

$m \leq 15$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$m \leq 15$

Interval Notation:

$(- \infty, 15]$