Solve the Inequality for x 3(x+2)>0

$3 (x + 2) > 0$

Step 1

Divide each term in $3 (x + 2) > 0$ by $3$ and simplify.

Divide each term in $3 (x + 2) > 0$ by $3$ .

$\frac{3 (x + 2)}{3} > \frac{0}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (x + 2)}{3} > \frac{0}{3}$

Divide $x + 2$ by $1$ .

$x + 2 > \frac{0}{3}$

Simplify the right side.

Divide $0$ by $3$ .

$x + 2 > 0$

Step 2

Subtract $2$ from both sides of the inequality.

$x > - 2$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$x > - 2$

Interval Notation:

$(- 2, \infty)$