Solve the Inequality for x 9x-71>3(3x-7u)

$9 x - 71 > 3 (3 x - 7 u)$

Step 1

Simplify $3 (3 x - 7 u)$ .

Rewrite.

$9 x - 71 > 0 + 0 + 3 (3 x - 7 u)$

Simplify by adding zeros.

$9 x - 71 > 3 (3 x - 7 u)$

Apply the distributive property.

$9 x - 71 > 3 (3 x) + 3 (- 7 u)$

Multiply.

Multiply $3$ by $3$ .

$9 x - 71 > 9 x + 3 (- 7 u)$

Multiply $- 7$ by $3$ .

$9 x - 71 > 9 x - 21 u$

Step 2

Move all terms containing $x$ to the left side of the inequality.

Subtract $9 x$ from both sides of the inequality.

$9 x - 71 - 9 x > - 21 u$

Combine the opposite terms in $9 x - 71 - 9 x$ .

Subtract $9 x$ from $9 x$ .

$0 - 71 > - 21 u$

Subtract $71$ from $0$ .

$- 71 > - 21 u$

Step 3

The variable $x$ got canceled.

All real numbers

Step 4

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$