Solve the Inequality for x x-3(x+2)>4

$x - 3 (x + 2) > 4$

Step 1

Simplify $x - 3 (x + 2)$ .

Simplify each term.

Apply the distributive property.

$x - 3 x - 3 \cdot 2 > 4$

Multiply $- 3$ by $2$ .

$x - 3 x - 6 > 4$

Subtract $3 x$ from $x$ .

$- 2 x - 6 > 4$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Add $6$ to both sides of the inequality.

$- 2 x > 4 + 6$

Add $4$ and $6$ .

$- 2 x > 10$

Step 3

Divide each term in $- 2 x > 10$ by $- 2$ and simplify.

Divide each term in $- 2 x > 10$ by $- 2$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 2 x}{- 2} < \frac{10}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} < \frac{10}{- 2}$

Divide $x$ by $1$ .

$x < \frac{10}{- 2}$

Simplify the right side.

Divide $10$ by $- 2$ .

$x < - 5$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x < - 5$

Interval Notation:

$(- \infty, - 5)$

Solve the Inequality for x x-3(x+2)>4

Related Questions

Support LCMGCF.com by disabling your adblocker.