Solve the Inequality for y 7+9y<19-3y

$7 + 9 y < 19 - 3 y$

Move all terms containing $y$ to the left side of the inequality.

Add $3 y$ to both sides of the inequality.

$7 + 9 y + 3 y < 19$

Add $9 y$ and $3 y$ .

$7 + 12 y < 19$

Move all terms not containing $y$ to the right side of the inequality.

Subtract $7$ from both sides of the inequality.

$12 y < 19 - 7$

Subtract $7$ from $19$ .

$12 y < 12$

Divide each term in $12 y < 12$ by $12$ and simplify.

Divide each term in $12 y < 12$ by $12$ .

$\frac{12 y}{12} < \frac{12}{12}$

Simplify the left side.

Cancel the common factor of $12$ .

Cancel the common factor.

$\frac{12 y}{12} < \frac{12}{12}$

Divide $y$ by $1$ .

$y < \frac{12}{12}$

Simplify the right side.

Divide $12$ by $12$ .

$y < 1$

The result can be shown in multiple forms.

Inequality Form:

$y < 1$

Interval Notation:

$(- \infty, 1)$