Solve the System of Equations -2x+y=8 y=(2x)/5-8

$- 2 x + y = 8$ $y = \frac{2 x}{5} - 8$

Replace all occurrences of $y$ with $\frac{2 x}{5} - 8$ in each equation.

Replace all occurrences of $y$ in $- 2 x + y = 8$ with $\frac{2 x}{5} - 8$ .

$- 2 x + \frac{2 x}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

Simplify the left side.

Simplify $- 2 x + \frac{2 x}{5} - 8$ .

Remove parentheses.

$- 2 x + \frac{2 x}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

To write $- 2 x$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$- 2 x \cdot \frac{5}{5} + \frac{2 x}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

Simplify terms.

Combine $- 2 x$ and $\frac{5}{5}$ .

$\frac{- 2 x \cdot 5}{5} + \frac{2 x}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

Combine the numerators over the common denominator.

$\frac{- 2 x \cdot 5 + 2 x}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

$\frac{- 2 x \cdot 5 + 2 x}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

Simplify each term.

Simplify the numerator.

Factor $2 x$ out of $- 2 x \cdot 5 + 2 x$ .

Factor $2 x$ out of $- 2 x \cdot 5$ .

$\frac{2 x (- 1 \cdot 5) + 2 x}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

Factor $2 x$ out of $2 x$ .

$\frac{2 x (- 1 \cdot 5) + 2 x (1)}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

Factor $2 x$ out of $2 x (- 1 \cdot 5) + 2 x (1)$ .

$\frac{2 x (- 1 \cdot 5 + 1)}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

$\frac{2 x (- 1 \cdot 5 + 1)}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

Multiply $- 1$ by $5$ .

$\frac{2 x (- 5 + 1)}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

Add $- 5$ and $1$ .

$\frac{2 x \cdot - 4}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

Multiply $- 4$ by $2$ .

$\frac{- 8 x}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

$\frac{- 8 x}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

Move the negative in front of the fraction.

$- \frac{8 x}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

$- \frac{8 x}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

$- \frac{8 x}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

$- \frac{8 x}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

$- \frac{8 x}{5} - 8 = 8$

$y = \frac{2 x}{5} - 8$

Solve for $x$ in $- \frac{8 x}{5} - 8 = 8$ .

Move all terms not containing $x$ to the right side of the equation.

Add $8$ to both sides of the equation.

$- \frac{8 x}{5} = 8 + 8$

$y = \frac{2 x}{5} - 8$

Add $8$ and $8$ .

$- \frac{8 x}{5} = 16$

$y = \frac{2 x}{5} - 8$

$- \frac{8 x}{5} = 16$

$y = \frac{2 x}{5} - 8$

Multiply both sides of the equation by $- \frac{5}{8}$ .

$- \frac{5}{8} \cdot (- \frac{8 x}{5}) = - \frac{5}{8} \cdot 16$

$y = \frac{2 x}{5} - 8$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{5}{8} (- \frac{8 x}{5})$ .

Cancel the common factor of $5$ .

Move the leading negative in $- \frac{5}{8}$ into the numerator.

$\frac{- 5}{8} \cdot (- \frac{8 x}{5}) = - \frac{5}{8} \cdot 16$

$y = \frac{2 x}{5} - 8$

Move the leading negative in $- \frac{8 x}{5}$ into the numerator.

$\frac{- 5}{8} \cdot \frac{- 8 x}{5} = - \frac{5}{8} \cdot 16$

$y = \frac{2 x}{5} - 8$

Factor $5$ out of $- 5$ .

$\frac{5 (- 1)}{8} \cdot \frac{- 8 x}{5} = - \frac{5}{8} \cdot 16$

$y = \frac{2 x}{5} - 8$

Cancel the common factor.

$\frac{5 \cdot - 1}{8} \cdot \frac{- 8 x}{5} = - \frac{5}{8} \cdot 16$

$y = \frac{2 x}{5} - 8$

Rewrite the expression.

$\frac{- 1}{8} \cdot (- 8 x) = - \frac{5}{8} \cdot 16$

$y = \frac{2 x}{5} - 8$

$\frac{- 1}{8} \cdot (- 8 x) = - \frac{5}{8} \cdot 16$

$y = \frac{2 x}{5} - 8$

Cancel the common factor of $8$ .

Factor $8$ out of $- 8 x$ .

$\frac{- 1}{8} \cdot (8 (- x)) = - \frac{5}{8} \cdot 16$

$y = \frac{2 x}{5} - 8$

Cancel the common factor.

$\frac{- 1}{8} \cdot (8 (- x)) = - \frac{5}{8} \cdot 16$

$y = \frac{2 x}{5} - 8$

Rewrite the expression.

$x = - \frac{5}{8} \cdot 16$

$y = \frac{2 x}{5} - 8$

$x = - \frac{5}{8} \cdot 16$

$y = \frac{2 x}{5} - 8$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - \frac{5}{8} \cdot 16$

$y = \frac{2 x}{5} - 8$

Multiply $x$ by $1$ .

$x = - \frac{5}{8} \cdot 16$

$y = \frac{2 x}{5} - 8$

$x = - \frac{5}{8} \cdot 16$

$y = \frac{2 x}{5} - 8$

$x = - \frac{5}{8} \cdot 16$

$y = \frac{2 x}{5} - 8$

$x = - \frac{5}{8} \cdot 16$

$y = \frac{2 x}{5} - 8$

Simplify the right side.

Simplify $- \frac{5}{8} \cdot 16$ .

Cancel the common factor of $8$ .

Move the leading negative in $- \frac{5}{8}$ into the numerator.

$x = \frac{- 5}{8} \cdot 16$

$y = \frac{2 x}{5} - 8$

Factor $8$ out of $16$ .

$x = \frac{- 5}{8} \cdot (8 (2))$

$y = \frac{2 x}{5} - 8$

Cancel the common factor.

$x = \frac{- 5}{8} \cdot (8 \cdot 2)$

$y = \frac{2 x}{5} - 8$

Rewrite the expression.

$x = - 5 \cdot 2$

$y = \frac{2 x}{5} - 8$

$x = - 5 \cdot 2$

$y = \frac{2 x}{5} - 8$

Multiply $- 5$ by $2$ .

$x = - 10$

$y = \frac{2 x}{5} - 8$

$x = - 10$

$y = \frac{2 x}{5} - 8$

$x = - 10$

$y = \frac{2 x}{5} - 8$

$x = - 10$

$y = \frac{2 x}{5} - 8$

$x = - 10$

$y = \frac{2 x}{5} - 8$

Replace all occurrences of $x$ with $- 10$ in each equation.

Replace all occurrences of $x$ in $y = \frac{2 x}{5} - 8$ with $- 10$ .

$y = \frac{2 (- 10)}{5} - 8$

$x = - 10$

Simplify the right side.

Simplify $\frac{2 (- 10)}{5} - 8$ .

Multiply $2$ by $- 10$ .

$y = \frac{- 20}{5} - 8$

$x = - 10$

Divide $- 20$ by $5$ .

$y = - 4 - 8$

$x = - 10$

Subtract $8$ from $- 4$ .

$y = - 12$

$x = - 10$

$y = - 12$

$x = - 10$

$y = - 12$

$x = - 10$

$y = - 12$

$x = - 10$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 10, - 12)$

The result can be shown in multiple forms.

Point Form:

$(- 10, - 12)$

Equation Form:

$x = - 10, y = - 12$

Solve the System of Equations -2x+y=8 y=(2x)/5-8

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