Solve the System of Equations 3x-4y+6z=-27 x+5y-2z=18 5x+y-3z=-8

$3 x - 4 y + 6 z = - 27$ $x + 5 y - 2 z = 18$ $5 x + y - 3 z = - 8$

Move all terms not containing $x$ to the right side of the equation.

Subtract $5 y$ from both sides of the equation.

$x - 2 z = 18 - 5 y$

$3 x - 4 y + 6 z = - 27$

$5 x + y - 3 z = - 8$

Add $2 z$ to both sides of the equation.

$x = 18 - 5 y + 2 z$

$3 x - 4 y + 6 z = - 27$

$5 x + y - 3 z = - 8$

$x = 18 - 5 y + 2 z$

$3 x - 4 y + 6 z = - 27$

$5 x + y - 3 z = - 8$

Replace all occurrences of $x$ with $18 - 5 y + 2 z$ in each equation.

Replace all occurrences of $x$ in $3 x - 4 y + 6 z = - 27$ with $18 - 5 y + 2 z$ .

$3 (18 - 5 y + 2 z) - 4 y + 6 z = - 27$

$x = 18 - 5 y + 2 z$

$5 x + y - 3 z = - 8$

Simplify the left side.

Simplify $3 (18 - 5 y + 2 z) - 4 y + 6 z$ .

Simplify each term.

Apply the distributive property.

$3 \cdot 18 + 3 (- 5 y) + 3 (2 z) - 4 y + 6 z = - 27$

$x = 18 - 5 y + 2 z$

$5 x + y - 3 z = - 8$

Simplify.

Multiply $3$ by $18$ .

$54 + 3 (- 5 y) + 3 (2 z) - 4 y + 6 z = - 27$

$x = 18 - 5 y + 2 z$

$5 x + y - 3 z = - 8$

Multiply $- 5$ by $3$ .

$54 - 15 y + 3 (2 z) - 4 y + 6 z = - 27$

$x = 18 - 5 y + 2 z$

$5 x + y - 3 z = - 8$

Multiply $2$ by $3$ .

$54 - 15 y + 6 z - 4 y + 6 z = - 27$

$x = 18 - 5 y + 2 z$

$5 x + y - 3 z = - 8$

$54 - 15 y + 6 z - 4 y + 6 z = - 27$

$x = 18 - 5 y + 2 z$

$5 x + y - 3 z = - 8$

$54 - 15 y + 6 z - 4 y + 6 z = - 27$

$x = 18 - 5 y + 2 z$

$5 x + y - 3 z = - 8$

Simplify by adding terms.

Subtract $4 y$ from $- 15 y$ .

$54 - 19 y + 6 z + 6 z = - 27$

$x = 18 - 5 y + 2 z$

$5 x + y - 3 z = - 8$

Add $6 z$ and $6 z$ .

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$5 x + y - 3 z = - 8$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$5 x + y - 3 z = - 8$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$5 x + y - 3 z = - 8$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$5 x + y - 3 z = - 8$

Replace all occurrences of $x$ in $5 x + y - 3 z = - 8$ with $18 - 5 y + 2 z$ .

$5 (18 - 5 y + 2 z) + y - 3 z = - 8$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

Simplify the left side.

Simplify $5 (18 - 5 y + 2 z) + y - 3 z$ .

Simplify each term.

Apply the distributive property.

$5 \cdot 18 + 5 (- 5 y) + 5 (2 z) + y - 3 z = - 8$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

Simplify.

Multiply $5$ by $18$ .

$90 + 5 (- 5 y) + 5 (2 z) + y - 3 z = - 8$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

Multiply $- 5$ by $5$ .

$90 - 25 y + 5 (2 z) + y - 3 z = - 8$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

Multiply $2$ by $5$ .

$90 - 25 y + 10 z + y - 3 z = - 8$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$90 - 25 y + 10 z + y - 3 z = - 8$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$90 - 25 y + 10 z + y - 3 z = - 8$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

Simplify by adding terms.

Add $- 25 y$ and $y$ .

$90 - 24 y + 10 z - 3 z = - 8$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

Subtract $3 z$ from $10 z$ .

$90 - 24 y + 7 z = - 8$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$90 - 24 y + 7 z = - 8$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$90 - 24 y + 7 z = - 8$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$90 - 24 y + 7 z = - 8$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$90 - 24 y + 7 z = - 8$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

Solve for $y$ in $90 - 24 y + 7 z = - 8$ .

Move all terms not containing $y$ to the right side of the equation.

Subtract $90$ from both sides of the equation.

$- 24 y + 7 z = - 8 - 90$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

Subtract $7 z$ from both sides of the equation.

$- 24 y = - 8 - 90 - 7 z$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

Subtract $90$ from $- 8$ .

$- 24 y = - 98 - 7 z$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$- 24 y = - 98 - 7 z$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

Divide each term in $- 24 y = - 98 - 7 z$ by $- 24$ and simplify.

Divide each term in $- 24 y = - 98 - 7 z$ by $- 24$ .

$\frac{- 24 y}{- 24} = \frac{- 98}{- 24} + \frac{- 7 z}{- 24}$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

Simplify the left side.

Cancel the common factor of $- 24$ .

Cancel the common factor.

$\frac{- 24 y}{- 24} = \frac{- 98}{- 24} + \frac{- 7 z}{- 24}$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

Divide $y$ by $1$ .

$y = \frac{- 98}{- 24} + \frac{- 7 z}{- 24}$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$y = \frac{- 98}{- 24} + \frac{- 7 z}{- 24}$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$y = \frac{- 98}{- 24} + \frac{- 7 z}{- 24}$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

Simplify the right side.

Simplify each term.

Cancel the common factor of $- 98$ and $- 24$ .

Factor $- 2$ out of $- 98$ .

$y = \frac{- 2 \cdot 49}{- 24} + \frac{- 7 z}{- 24}$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

Cancel the common factors.

Factor $- 2$ out of $- 24$ .

$y = \frac{- 2 \cdot 49}{- 2 \cdot 12} + \frac{- 7 z}{- 24}$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

Cancel the common factor.

$y = \frac{- 2 \cdot 49}{- 2 \cdot 12} + \frac{- 7 z}{- 24}$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

Rewrite the expression.

$y = \frac{49}{12} + \frac{- 7 z}{- 24}$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$y = \frac{49}{12} + \frac{- 7 z}{- 24}$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$y = \frac{49}{12} + \frac{- 7 z}{- 24}$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

Dividing two negative values results in a positive value.

$y = \frac{49}{12} + \frac{7 z}{24}$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$y = \frac{49}{12} + \frac{7 z}{24}$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$y = \frac{49}{12} + \frac{7 z}{24}$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$y = \frac{49}{12} + \frac{7 z}{24}$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

$y = \frac{49}{12} + \frac{7 z}{24}$

$54 - 19 y + 12 z = - 27$

$x = 18 - 5 y + 2 z$

Replace all occurrences of $y$ with $\frac{49}{12} + \frac{7 z}{24}$ in each equation.

Replace all occurrences of $y$ in $54 - 19 y + 12 z = - 27$ with $\frac{49}{12} + \frac{7 z}{24}$ .

$54 - 19 (\frac{49}{12} + \frac{7 z}{24}) + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Simplify the left side.

Simplify $54 - 19 (\frac{49}{12} + \frac{7 z}{24}) + 12 z$ .

Simplify each term.

Apply the distributive property.

$54 - 19 (\frac{49}{12}) - 19 \frac{7 z}{24} + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Multiply $- 19 (\frac{49}{12})$ .

Combine $- 19$ and $\frac{49}{12}$ .

$54 + \frac{- 19 \cdot 49}{12} - 19 \frac{7 z}{24} + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Multiply $- 19$ by $49$ .

$54 + \frac{- 931}{12} - 19 \frac{7 z}{24} + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

$54 + \frac{- 931}{12} - 19 \frac{7 z}{24} + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Multiply $- 19 \frac{7 z}{24}$ .

Combine $- 19$ and $\frac{7 z}{24}$ .

$54 + \frac{- 931}{12} + \frac{- 19 (7 z)}{24} + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Multiply $7$ by $- 19$ .

$54 + \frac{- 931}{12} + \frac{- 133 z}{24} + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

$54 + \frac{- 931}{12} + \frac{- 133 z}{24} + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Simplify each term.

Move the negative in front of the fraction.

$54 - \frac{931}{12} + \frac{- 133 z}{24} + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Move the negative in front of the fraction.

$54 - \frac{931}{12} - \frac{133 z}{24} + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

$54 - \frac{931}{12} - \frac{133 z}{24} + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

$54 - \frac{931}{12} - \frac{133 z}{24} + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

To write $54$ as a fraction with a common denominator, multiply by $\frac{12}{12}$ .

$54 \cdot \frac{12}{12} - \frac{931}{12} - \frac{133 z}{24} + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Combine $54$ and $\frac{12}{12}$ .

$\frac{54 \cdot 12}{12} - \frac{931}{12} - \frac{133 z}{24} + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Combine the numerators over the common denominator.

$\frac{54 \cdot 12 - 931}{12} - \frac{133 z}{24} + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Simplify the numerator.

Multiply $54$ by $12$ .

$\frac{648 - 931}{12} - \frac{133 z}{24} + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Subtract $931$ from $648$ .

$\frac{- 283}{12} - \frac{133 z}{24} + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

$\frac{- 283}{12} - \frac{133 z}{24} + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Move the negative in front of the fraction.

$- \frac{283}{12} - \frac{133 z}{24} + 12 z = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

To write $12 z$ as a fraction with a common denominator, multiply by $\frac{24}{24}$ .

$- \frac{283}{12} - \frac{133 z}{24} + 12 z \cdot \frac{24}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Simplify terms.

Combine $12 z$ and $\frac{24}{24}$ .

$- \frac{283}{12} - \frac{133 z}{24} + \frac{12 z \cdot 24}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Combine the numerators over the common denominator.

$- \frac{283}{12} + \frac{- 133 z + 12 z \cdot 24}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

$- \frac{283}{12} + \frac{- 133 z + 12 z \cdot 24}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Simplify each term.

Simplify the numerator.

Factor $z$ out of $- 133 z + 12 z \cdot 24$ .

Factor $z$ out of $- 133 z$ .

$- \frac{283}{12} + \frac{z \cdot - 133 + 12 z \cdot 24}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Factor $z$ out of $12 z \cdot 24$ .

$- \frac{283}{12} + \frac{z \cdot - 133 + z (12 \cdot 24)}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Factor $z$ out of $z \cdot - 133 + z (12 \cdot 24)$ .

$- \frac{283}{12} + \frac{z (- 133 + 12 \cdot 24)}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

$- \frac{283}{12} + \frac{z (- 133 + 12 \cdot 24)}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Multiply $12$ by $24$ .

$- \frac{283}{12} + \frac{z (- 133 + 288)}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Add $- 133$ and $288$ .

$- \frac{283}{12} + \frac{z \cdot 155}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

$- \frac{283}{12} + \frac{z \cdot 155}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Move $155$ to the left of $z$ .

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - 5 y + 2 z$

Replace all occurrences of $y$ in $x = 18 - 5 y + 2 z$ with $\frac{49}{12} + \frac{7 z}{24}$ .

$x = 18 - 5 (\frac{49}{12} + \frac{7 z}{24}) + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Simplify the right side.

Simplify $18 - 5 (\frac{49}{12} + \frac{7 z}{24}) + 2 z$ .

Simplify each term.

Apply the distributive property.

$x = 18 - 5 (\frac{49}{12}) - 5 \frac{7 z}{24} + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Multiply $- 5 (\frac{49}{12})$ .

Combine $- 5$ and $\frac{49}{12}$ .

$x = 18 + \frac{- 5 \cdot 49}{12} - 5 \frac{7 z}{24} + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Multiply $- 5$ by $49$ .

$x = 18 + \frac{- 245}{12} - 5 \frac{7 z}{24} + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 + \frac{- 245}{12} - 5 \frac{7 z}{24} + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Multiply $- 5 \frac{7 z}{24}$ .

Combine $- 5$ and $\frac{7 z}{24}$ .

$x = 18 + \frac{- 245}{12} + \frac{- 5 (7 z)}{24} + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Multiply $7$ by $- 5$ .

$x = 18 + \frac{- 245}{12} + \frac{- 35 z}{24} + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 + \frac{- 245}{12} + \frac{- 35 z}{24} + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Simplify each term.

Move the negative in front of the fraction.

$x = 18 - \frac{245}{12} + \frac{- 35 z}{24} + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Move the negative in front of the fraction.

$x = 18 - \frac{245}{12} - \frac{35 z}{24} + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - \frac{245}{12} - \frac{35 z}{24} + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = 18 - \frac{245}{12} - \frac{35 z}{24} + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

To write $18$ as a fraction with a common denominator, multiply by $\frac{12}{12}$ .

$x = 18 \cdot \frac{12}{12} - \frac{245}{12} - \frac{35 z}{24} + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Combine $18$ and $\frac{12}{12}$ .

$x = \frac{18 \cdot 12}{12} - \frac{245}{12} - \frac{35 z}{24} + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Combine the numerators over the common denominator.

$x = \frac{18 \cdot 12 - 245}{12} - \frac{35 z}{24} + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Simplify the numerator.

Multiply $18$ by $12$ .

$x = \frac{216 - 245}{12} - \frac{35 z}{24} + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Subtract $245$ from $216$ .

$x = \frac{- 29}{12} - \frac{35 z}{24} + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = \frac{- 29}{12} - \frac{35 z}{24} + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Move the negative in front of the fraction.

$x = - \frac{29}{12} - \frac{35 z}{24} + 2 z$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

To write $2 z$ as a fraction with a common denominator, multiply by $\frac{24}{24}$ .

$x = - \frac{29}{12} - \frac{35 z}{24} + 2 z \cdot \frac{24}{24}$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Simplify terms.

Combine $2 z$ and $\frac{24}{24}$ .

$x = - \frac{29}{12} - \frac{35 z}{24} + \frac{2 z \cdot 24}{24}$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Combine the numerators over the common denominator.

$x = - \frac{29}{12} + \frac{- 35 z + 2 z \cdot 24}{24}$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = - \frac{29}{12} + \frac{- 35 z + 2 z \cdot 24}{24}$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Simplify each term.

Simplify the numerator.

Factor $z$ out of $- 35 z + 2 z \cdot 24$ .

Factor $z$ out of $- 35 z$ .

$x = - \frac{29}{12} + \frac{z \cdot - 35 + 2 z \cdot 24}{24}$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Factor $z$ out of $2 z \cdot 24$ .

$x = - \frac{29}{12} + \frac{z \cdot - 35 + z (2 \cdot 24)}{24}$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Factor $z$ out of $z \cdot - 35 + z (2 \cdot 24)$ .

$x = - \frac{29}{12} + \frac{z (- 35 + 2 \cdot 24)}{24}$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = - \frac{29}{12} + \frac{z (- 35 + 2 \cdot 24)}{24}$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Multiply $2$ by $24$ .

$x = - \frac{29}{12} + \frac{z (- 35 + 48)}{24}$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Add $- 35$ and $48$ .

$x = - \frac{29}{12} + \frac{z \cdot 13}{24}$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = - \frac{29}{12} + \frac{z \cdot 13}{24}$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Move $13$ to the left of $z$ .

$x = - \frac{29}{12} + \frac{13 z}{24}$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$- \frac{283}{12} + \frac{155 z}{24} = - 27$

$y = \frac{49}{12} + \frac{7 z}{24}$

Solve for $z$ in $- \frac{283}{12} + \frac{155 z}{24} = - 27$ .

Move all terms not containing $z$ to the right side of the equation.

Add $\frac{283}{12}$ to both sides of the equation.

$\frac{155 z}{24} = - 27 + \frac{283}{12}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

To write $- 27$ as a fraction with a common denominator, multiply by $\frac{12}{12}$ .

$\frac{155 z}{24} = - 27 \cdot \frac{12}{12} + \frac{283}{12}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Combine $- 27$ and $\frac{12}{12}$ .

$\frac{155 z}{24} = \frac{- 27 \cdot 12}{12} + \frac{283}{12}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Combine the numerators over the common denominator.

$\frac{155 z}{24} = \frac{- 27 \cdot 12 + 283}{12}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Simplify the numerator.

Multiply $- 27$ by $12$ .

$\frac{155 z}{24} = \frac{- 324 + 283}{12}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Add $- 324$ and $283$ .

$\frac{155 z}{24} = \frac{- 41}{12}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$\frac{155 z}{24} = \frac{- 41}{12}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Move the negative in front of the fraction.

$\frac{155 z}{24} = - \frac{41}{12}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$\frac{155 z}{24} = - \frac{41}{12}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Multiply both sides of the equation by $\frac{24}{155}$ .

$\frac{24}{155} \cdot \frac{155 z}{24} = \frac{24}{155} \cdot (- \frac{41}{12})$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{24}{155} \cdot \frac{155 z}{24}$ .

Cancel the common factor of $24$ .

Cancel the common factor.

$\frac{24}{155} \cdot \frac{155 z}{24} = \frac{24}{155} \cdot (- \frac{41}{12})$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Rewrite the expression.

$\frac{1}{155} \cdot (155 z) = \frac{24}{155} \cdot (- \frac{41}{12})$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$\frac{1}{155} \cdot (155 z) = \frac{24}{155} \cdot (- \frac{41}{12})$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Cancel the common factor of $155$ .

Factor $155$ out of $155 z$ .

$\frac{1}{155} \cdot (155 (z)) = \frac{24}{155} \cdot (- \frac{41}{12})$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Cancel the common factor.

$\frac{1}{155} \cdot (155 z) = \frac{24}{155} \cdot (- \frac{41}{12})$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Rewrite the expression.

$z = \frac{24}{155} \cdot (- \frac{41}{12})$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$z = \frac{24}{155} \cdot (- \frac{41}{12})$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$z = \frac{24}{155} \cdot (- \frac{41}{12})$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$z = \frac{24}{155} \cdot (- \frac{41}{12})$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Simplify the right side.

Simplify $\frac{24}{155} (- \frac{41}{12})$ .

Cancel the common factor of $12$ .

Move the leading negative in $- \frac{41}{12}$ into the numerator.

$z = \frac{24}{155} \cdot \frac{- 41}{12}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Factor $12$ out of $24$ .

$z = \frac{12 (2)}{155} \cdot \frac{- 41}{12}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Cancel the common factor.

$z = \frac{12 \cdot 2}{155} \cdot \frac{- 41}{12}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Rewrite the expression.

$z = \frac{2}{155} \cdot - 41$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$z = \frac{2}{155} \cdot - 41$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Combine $\frac{2}{155}$ and $- 41$ .

$z = \frac{2 \cdot - 41}{155}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Simplify the expression.

Multiply $2$ by $- 41$ .

$z = \frac{- 82}{155}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Move the negative in front of the fraction.

$z = - \frac{82}{155}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$z = - \frac{82}{155}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$z = - \frac{82}{155}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$z = - \frac{82}{155}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$z = - \frac{82}{155}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$z = - \frac{82}{155}$

$x = - \frac{29}{12} + \frac{13 z}{24}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Replace all occurrences of $z$ with $- \frac{82}{155}$ in each equation.

Replace all occurrences of $z$ in $x = - \frac{29}{12} + \frac{13 z}{24}$ with $- \frac{82}{155}$ .

$x = - \frac{29}{12} + \frac{13 (- \frac{82}{155})}{24}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Simplify the right side.

Simplify $- \frac{29}{12} + \frac{13 (- \frac{82}{155})}{24}$ .

Simplify each term.

Simplify the numerator.

Multiply $- 1$ by $13$ .

$x = - \frac{29}{12} + \frac{- 13 (\frac{82}{155})}{24}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Combine $- 13$ and $\frac{82}{155}$ .

$x = - \frac{29}{12} + \frac{\frac{- 13 \cdot 82}{155}}{24}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = - \frac{29}{12} + \frac{\frac{- 13 \cdot 82}{155}}{24}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Multiply $- 13$ by $82$ .

$x = - \frac{29}{12} + \frac{\frac{- 1066}{155}}{24}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Move the negative in front of the fraction.

$x = - \frac{29}{12} + \frac{- \frac{1066}{155}}{24}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Multiply the numerator by the reciprocal of the denominator.

$x = - \frac{29}{12} - \frac{1066}{155} \cdot \frac{1}{24}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{1066}{155}$ into the numerator.

$x = - \frac{29}{12} + \frac{- 1066}{155} \cdot \frac{1}{24}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Factor $2$ out of $- 1066$ .

$x = - \frac{29}{12} + \frac{2 (- 533)}{155} \cdot \frac{1}{24}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Factor $2$ out of $24$ .

$x = - \frac{29}{12} + \frac{2 \cdot - 533}{155} \cdot \frac{1}{2 \cdot 12}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Cancel the common factor.

$x = - \frac{29}{12} + \frac{2 \cdot - 533}{155} \cdot \frac{1}{2 \cdot 12}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Rewrite the expression.

$x = - \frac{29}{12} + \frac{- 533}{155} \cdot \frac{1}{12}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = - \frac{29}{12} + \frac{- 533}{155} \cdot \frac{1}{12}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Multiply $\frac{- 533}{155}$ by $\frac{1}{12}$ .

$x = - \frac{29}{12} + \frac{- 533}{155 \cdot 12}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Multiply $155$ by $12$ .

$x = - \frac{29}{12} + \frac{- 533}{1860}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Move the negative in front of the fraction.

$x = - \frac{29}{12} - \frac{533}{1860}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = - \frac{29}{12} - \frac{533}{1860}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

To write $- \frac{29}{12}$ as a fraction with a common denominator, multiply by $\frac{155}{155}$ .

$x = - \frac{29}{12} \cdot \frac{155}{155} - \frac{533}{1860}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Write each expression with a common denominator of $1860$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{29}{12}$ by $\frac{155}{155}$ .

$x = - \frac{29 \cdot 155}{12 \cdot 155} - \frac{533}{1860}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Multiply $12$ by $155$ .

$x = - \frac{29 \cdot 155}{1860} - \frac{533}{1860}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = - \frac{29 \cdot 155}{1860} - \frac{533}{1860}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Combine the numerators over the common denominator.

$x = \frac{- 29 \cdot 155 - 533}{1860}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Simplify the numerator.

Multiply $- 29$ by $155$ .

$x = \frac{- 4495 - 533}{1860}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Subtract $533$ from $- 4495$ .

$x = \frac{- 5028}{1860}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = \frac{- 5028}{1860}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Cancel the common factor of $- 5028$ and $1860$ .

Factor $12$ out of $- 5028$ .

$x = \frac{12 (- 419)}{1860}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Cancel the common factors.

Factor $12$ out of $1860$ .

$x = \frac{12 \cdot - 419}{12 \cdot 155}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Cancel the common factor.

$x = \frac{12 \cdot - 419}{12 \cdot 155}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Rewrite the expression.

$x = \frac{- 419}{155}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = \frac{- 419}{155}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = \frac{- 419}{155}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Move the negative in front of the fraction.

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{7 z}{24}$

Replace all occurrences of $z$ in $y = \frac{49}{12} + \frac{7 z}{24}$ with $- \frac{82}{155}$ .

$y = \frac{49}{12} + \frac{7 (- \frac{82}{155})}{24}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Simplify the right side.

Simplify $\frac{49}{12} + \frac{7 (- \frac{82}{155})}{24}$ .

Simplify each term.

Simplify the numerator.

Multiply $- 1$ by $7$ .

$y = \frac{49}{12} + \frac{- 7 (\frac{82}{155})}{24}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Combine $- 7$ and $\frac{82}{155}$ .

$y = \frac{49}{12} + \frac{\frac{- 7 \cdot 82}{155}}{24}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{\frac{- 7 \cdot 82}{155}}{24}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Multiply $- 7$ by $82$ .

$y = \frac{49}{12} + \frac{\frac{- 574}{155}}{24}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Move the negative in front of the fraction.

$y = \frac{49}{12} + \frac{- \frac{574}{155}}{24}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Multiply the numerator by the reciprocal of the denominator.

$y = \frac{49}{12} - \frac{574}{155} \cdot \frac{1}{24}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{574}{155}$ into the numerator.

$y = \frac{49}{12} + \frac{- 574}{155} \cdot \frac{1}{24}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Factor $2$ out of $- 574$ .

$y = \frac{49}{12} + \frac{2 (- 287)}{155} \cdot \frac{1}{24}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Factor $2$ out of $24$ .

$y = \frac{49}{12} + \frac{2 \cdot - 287}{155} \cdot \frac{1}{2 \cdot 12}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Cancel the common factor.

$y = \frac{49}{12} + \frac{2 \cdot - 287}{155} \cdot \frac{1}{2 \cdot 12}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Rewrite the expression.

$y = \frac{49}{12} + \frac{- 287}{155} \cdot \frac{1}{12}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} + \frac{- 287}{155} \cdot \frac{1}{12}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Multiply $\frac{- 287}{155}$ by $\frac{1}{12}$ .

$y = \frac{49}{12} + \frac{- 287}{155 \cdot 12}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Multiply $155$ by $12$ .

$y = \frac{49}{12} + \frac{- 287}{1860}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Move the negative in front of the fraction.

$y = \frac{49}{12} - \frac{287}{1860}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

$y = \frac{49}{12} - \frac{287}{1860}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

To write $\frac{49}{12}$ as a fraction with a common denominator, multiply by $\frac{155}{155}$ .

$y = \frac{49}{12} \cdot \frac{155}{155} - \frac{287}{1860}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Write each expression with a common denominator of $1860$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{49}{12}$ by $\frac{155}{155}$ .

$y = \frac{49 \cdot 155}{12 \cdot 155} - \frac{287}{1860}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Multiply $12$ by $155$ .

$y = \frac{49 \cdot 155}{1860} - \frac{287}{1860}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

$y = \frac{49 \cdot 155}{1860} - \frac{287}{1860}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Combine the numerators over the common denominator.

$y = \frac{49 \cdot 155 - 287}{1860}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Simplify the numerator.

Multiply $49$ by $155$ .

$y = \frac{7595 - 287}{1860}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Subtract $287$ from $7595$ .

$y = \frac{7308}{1860}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

$y = \frac{7308}{1860}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Cancel the common factor of $7308$ and $1860$ .

Factor $12$ out of $7308$ .

$y = \frac{12 (609)}{1860}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Cancel the common factors.

Factor $12$ out of $1860$ .

$y = \frac{12 \cdot 609}{12 \cdot 155}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Cancel the common factor.

$y = \frac{12 \cdot 609}{12 \cdot 155}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

Rewrite the expression.

$y = \frac{609}{155}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

$y = \frac{609}{155}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

$y = \frac{609}{155}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

$y = \frac{609}{155}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

$y = \frac{609}{155}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

$y = \frac{609}{155}$

$x = - \frac{419}{155}$

$z = - \frac{82}{155}$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- \frac{419}{155}, \frac{609}{155}, - \frac{82}{155})$

The result can be shown in multiple forms.

Point Form:

$(- \frac{419}{155}, \frac{609}{155}, - \frac{82}{155})$

Equation Form:

$x = - \frac{419}{155}, y = \frac{609}{155}, z = - \frac{82}{155}$

Solve the System of Equations 3x-4y+6z=-27 x+5y-2z=18 5x+y-3z=-8

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