Solve the System of Equations 5y=15x-40 y=3x-8

$5 y = 15 x - 40$ $y = 3 x - 8$

Step 1

Replace all occurrences of $y$ with $3 x - 8$ in each equation.

Replace all occurrences of $y$ in $5 y = 15 x - 40$ with $3 x - 8$ .

$5 (3 x - 8) = 15 x - 40$

$y = 3 x - 8$

Simplify the left side.

Simplify $5 (3 x - 8)$ .

Apply the distributive property.

$5 (3 x) + 5 \cdot - 8 = 15 x - 40$

$y = 3 x - 8$

Multiply.

Multiply $3$ by $5$ .

$15 x + 5 \cdot - 8 = 15 x - 40$

$y = 3 x - 8$

Multiply $5$ by $- 8$ .

$15 x - 40 = 15 x - 40$

$y = 3 x - 8$

$15 x - 40 = 15 x - 40$

$y = 3 x - 8$

$15 x - 40 = 15 x - 40$

$y = 3 x - 8$

$15 x - 40 = 15 x - 40$

$y = 3 x - 8$

$15 x - 40 = 15 x - 40$

$y = 3 x - 8$

Step 2

Remove any equations from the system that are always true.

$y = 3 x - 8$

Step 3

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