Solve the System of Equations -x+y=-2 4x-4y=8

$- x + y = - 2$ $4 x - 4 y = 8$

Step 1

Add $x$ to both sides of the equation.

$y = - 2 + x$

$4 x - 4 y = 8$

Step 2

Replace all occurrences of $y$ with $- 2 + x$ in each equation.

Replace all occurrences of $y$ in $4 x - 4 y = 8$ with $- 2 + x$ .

$4 x - 4 (- 2 + x) = 8$

$y = - 2 + x$

Simplify the left side.

Simplify $4 x - 4 (- 2 + x)$ .

Simplify each term.

Apply the distributive property.

$4 x - 4 \cdot - 2 - 4 x = 8$

$y = - 2 + x$

Multiply $- 4$ by $- 2$ .

$4 x + 8 - 4 x = 8$

$y = - 2 + x$

$4 x + 8 - 4 x = 8$

$y = - 2 + x$

Combine the opposite terms in $4 x + 8 - 4 x$ .

Subtract $4 x$ from $4 x$ .

$0 + 8 = 8$

$y = - 2 + x$

Add $0$ and $8$ .

$8 = 8$

$y = - 2 + x$

$8 = 8$

$y = - 2 + x$

$8 = 8$

$y = - 2 + x$

$8 = 8$

$y = - 2 + x$

$8 = 8$

$y = - 2 + x$

Step 3

Remove any equations from the system that are always true.

$y = - 2 + x$

Step 4