Solve the System of Equations y=-4/3x-5 x=-3

$y = - \frac{4}{3} x - 5$ $x = - 3$

Replace all occurrences of $x$ with $- 3$ in each equation.

Replace all occurrences of $x$ in $y = - \frac{4}{3} x - 5$ with $- 3$ .

$y = - \frac{4}{3} \cdot - 3 - 5$

$x = - 3$

Simplify the right side.

Simplify $- \frac{4}{3} \cdot - 3 - 5$ .

Simplify each term.

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{4}{3}$ into the numerator.

$y = \frac{- 4}{3} \cdot - 3 - 5$

$x = - 3$

Factor $3$ out of $- 3$ .

$y = \frac{- 4}{3} \cdot (3 (- 1)) - 5$

$x = - 3$

Cancel the common factor.

$y = \frac{- 4}{3} \cdot (3 \cdot - 1) - 5$

$x = - 3$

Rewrite the expression.

$y = - 4 \cdot - 1 - 5$

$x = - 3$

$y = - 4 \cdot - 1 - 5$

$x = - 3$

Multiply $- 4$ by $- 1$ .

$y = 4 - 5$

$x = - 3$

$y = 4 - 5$

$x = - 3$

Subtract $5$ from $4$ .

$y = - 1$

$x = - 3$

$y = - 1$

$x = - 3$

$y = - 1$

$x = - 3$

$y = - 1$

$x = - 3$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 3, - 1)$

The result can be shown in multiple forms.

Point Form:

$(- 3, - 1)$

Equation Form:

$x = - 3, y = - 1$