Solve the System of Inequalities y-1>=7 or y+3<-1

$y - 1 \geq 7$ or $y + 3 < - 1$

Move all terms not containing $y$ to the right side of the inequality.

Add $1$ to both sides of the inequality.

$y \geq 7 + 1$ or $y + 3 < - 1$

Add $7$ and $1$ .

$y \geq 8$ or $y + 3 < - 1$

Move all terms not containing $y$ to the right side of the inequality.

Subtract $3$ from both sides of the inequality.

$y \geq 8$ or $y < - 1 - 3$

Subtract $3$ from $- 1$ .

$y \geq 8$ or $y < - 4$

The union consists of all of the elements that are contained in each interval.

$y < - 4$ or $y \geq 8$

The result can be shown in multiple forms.

Inequality Form:

$y < - 4 or y \geq 8$

Interval Notation:

$(- \infty, - 4) \cup [8, \infty)$