Solve Using the Quadratic Formula 2n^2-3n=7

$2 n^{2} - 3 n = 7$

Step 1

Subtract $7$ from both sides of the equation.

$2 n^{2} - 3 n - 7 = 0$

Step 2

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 3

Substitute the values $a = 2$ , $b = - 3$ , and $c = - 7$ into the quadratic formula and solve for $n$ .

$\frac{3 \pm \sqrt{{(- 3)}^{2} - 4 \cdot (2 \cdot - 7)}}{2 \cdot 2}$

Step 4

Simplify.

Simplify the numerator.

Raise $- 3$ to the power of $2$ .

$n = \frac{3 \pm \sqrt{9 - 4 \cdot 2 \cdot - 7}}{2 \cdot 2}$

Multiply $- 4 \cdot 2 \cdot - 7$ .

Multiply $- 4$ by $2$ .

$n = \frac{3 \pm \sqrt{9 - 8 \cdot - 7}}{2 \cdot 2}$

Multiply $- 8$ by $- 7$ .

$n = \frac{3 \pm \sqrt{9 + 56}}{2 \cdot 2}$

Add $9$ and $56$ .

$n = \frac{3 \pm \sqrt{65}}{2 \cdot 2}$

Multiply $2$ by $2$ .

$n = \frac{3 \pm \sqrt{65}}{4}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$n = \frac{3 \pm \sqrt{65}}{4}$

Decimal Form:

$n = 2.76556443 \dots, - 1.26556443 \dots$