Solve Using the Quadratic Formula 3x^2-10x=-2

$3 x^{2} - 10 x = - 2$

Step 1

Add $2$ to both sides of the equation.

$3 x^{2} - 10 x + 2 = 0$

Step 2

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 3

Substitute the values $a = 3$ , $b = - 10$ , and $c = 2$ into the quadratic formula and solve for $x$ .

$\frac{10 \pm \sqrt{{(- 10)}^{2} - 4 \cdot (3 \cdot 2)}}{2 \cdot 3}$

Step 4

Simplify.

Simplify the numerator.

Raise $- 10$ to the power of $2$ .

$x = \frac{10 \pm \sqrt{100 - 4 \cdot 3 \cdot 2}}{2 \cdot 3}$

Multiply $- 4 \cdot 3 \cdot 2$ .

Multiply $- 4$ by $3$ .

$x = \frac{10 \pm \sqrt{100 - 12 \cdot 2}}{2 \cdot 3}$

Multiply $- 12$ by $2$ .

$x = \frac{10 \pm \sqrt{100 - 24}}{2 \cdot 3}$

Subtract $24$ from $100$ .

$x = \frac{10 \pm \sqrt{76}}{2 \cdot 3}$

Rewrite $76$ as $2^{2} \cdot 19$ .

Factor $4$ out of $76$ .

$x = \frac{10 \pm \sqrt{4 (19)}}{2 \cdot 3}$

Rewrite $4$ as $2^{2}$ .

$x = \frac{10 \pm \sqrt{2^{2} \cdot 19}}{2 \cdot 3}$

Pull terms out from under the radical.

$x = \frac{10 \pm 2 \sqrt{19}}{2 \cdot 3}$

Multiply $2$ by $3$ .

$x = \frac{10 \pm 2 \sqrt{19}}{6}$

Simplify $\frac{10 \pm 2 \sqrt{19}}{6}$ .

$x = \frac{5 \pm \sqrt{19}}{3}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$x = \frac{5 \pm \sqrt{19}}{3}$

Decimal Form:

$x = 3.11963298 \dots, 0.21370035 \dots$