Solve Using the Quadratic Formula p^2+3p-9=0

$p^{2} + 3 p - 9 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 1$ , $b = 3$ , and $c = - 9$ into the quadratic formula and solve for $p$ .

$\frac{- 3 \pm \sqrt{3^{2} - 4 \cdot (1 \cdot - 9)}}{2 \cdot 1}$

Step 3

Simplify.

Simplify the numerator.

Raise $3$ to the power of $2$ .

$p = \frac{- 3 \pm \sqrt{9 - 4 \cdot 1 \cdot - 9}}{2 \cdot 1}$

Multiply $- 4 \cdot 1 \cdot - 9$ .

Multiply $- 4$ by $1$ .

$p = \frac{- 3 \pm \sqrt{9 - 4 \cdot - 9}}{2 \cdot 1}$

Multiply $- 4$ by $- 9$ .

$p = \frac{- 3 \pm \sqrt{9 + 36}}{2 \cdot 1}$

Add $9$ and $36$ .

$p = \frac{- 3 \pm \sqrt{45}}{2 \cdot 1}$

Rewrite $45$ as $3^{2} \cdot 5$ .

Factor $9$ out of $45$ .

$p = \frac{- 3 \pm \sqrt{9 (5)}}{2 \cdot 1}$

Rewrite $9$ as $3^{2}$ .

$p = \frac{- 3 \pm \sqrt{3^{2} \cdot 5}}{2 \cdot 1}$

Pull terms out from under the radical.

$p = \frac{- 3 \pm 3 \sqrt{5}}{2 \cdot 1}$

Multiply $2$ by $1$ .

$p = \frac{- 3 \pm 3 \sqrt{5}}{2}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$p = \frac{- 3 \pm 3 \sqrt{5}}{2}$

Decimal Form:

$p = 1.85410196 \dots, - 4.85410196 \dots$