Solve Using the Square Root Property 3y^2=96

$3 y^{2} = 96$

Step 1

Divide each term in $3 y^{2} = 96$ by $3$ and simplify.

Divide each term in $3 y^{2} = 96$ by $3$ .

$\frac{3 y^{2}}{3} = \frac{96}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y^{2}}{3} = \frac{96}{3}$

Divide $y^{2}$ by $1$ .

$y^{2} = \frac{96}{3}$

Simplify the right side.

Divide $96$ by $3$ .

$y^{2} = 32$

Step 2

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$y = \pm \sqrt{32}$

Step 3

Simplify $\pm \sqrt{32}$ .

Rewrite $32$ as $4^{2} \cdot 2$ .

Factor $16$ out of $32$ .

$y = \pm \sqrt{16 (2)}$

Rewrite $16$ as $4^{2}$ .

$y = \pm \sqrt{4^{2} \cdot 2}$

Pull terms out from under the radical.

$y = \pm 4 \sqrt{2}$

Step 4

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$y = 4 \sqrt{2}$

Next, use the negative value of the $\pm$ to find the second solution.

$y = - 4 \sqrt{2}$

The complete solution is the result of both the positive and negative portions of the solution.

$y = 4 \sqrt{2}, - 4 \sqrt{2}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$y = 4 \sqrt{2}, - 4 \sqrt{2}$

Decimal Form:

$y = 5.65685424 \dots, - 5.65685424 \dots$