Solve Using the Square Root Property 49x^2+2=6

$49 x^{2} + 2 = 6$

Step 1

Move all terms not containing $x$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$49 x^{2} = 6 - 2$

Subtract $2$ from $6$ .

$49 x^{2} = 4$

Step 2

Divide each term in $49 x^{2} = 4$ by $49$ and simplify.

Divide each term in $49 x^{2} = 4$ by $49$ .

$\frac{49 x^{2}}{49} = \frac{4}{49}$

Simplify the left side.

Cancel the common factor of $49$ .

Cancel the common factor.

$\frac{49 x^{2}}{49} = \frac{4}{49}$

Divide $x^{2}$ by $1$ .

$x^{2} = \frac{4}{49}$

Step 3

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{\frac{4}{49}}$

Step 4

Simplify $\pm \sqrt{\frac{4}{49}}$ .

Rewrite $\sqrt{\frac{4}{49}}$ as $\frac{\sqrt{4}}{\sqrt{49}}$ .

$x = \pm \frac{\sqrt{4}}{\sqrt{49}}$

Simplify the numerator.

Rewrite $4$ as $2^{2}$ .

$x = \pm \frac{\sqrt{2^{2}}}{\sqrt{49}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm \frac{2}{\sqrt{49}}$

Simplify the denominator.

Rewrite $49$ as $7^{2}$ .

$x = \pm \frac{2}{\sqrt{7^{2}}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm \frac{2}{7}$

Step 5

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = \frac{2}{7}$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - \frac{2}{7}$

The complete solution is the result of both the positive and negative portions of the solution.

$x = \frac{2}{7}, - \frac{2}{7}$