Write as a Function of x x^2+3y=3

$x^{2} + 3 y = 3$

Step 1

Subtract $x^{2}$ from both sides of the equation.

$3 y = 3 - x^{2}$

Step 2

Divide each term in $3 y = 3 - x^{2}$ by $3$ and simplify.

Divide each term in $3 y = 3 - x^{2}$ by $3$ .

$\frac{3 y}{3} = \frac{3}{3} + \frac{- x^{2}}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{3}{3} + \frac{- x^{2}}{3}$

Divide $y$ by $1$ .

$y = \frac{3}{3} + \frac{- x^{2}}{3}$

Simplify the right side.

Simplify each term.

Divide $3$ by $3$ .

$y = 1 + \frac{- x^{2}}{3}$

Move the negative in front of the fraction.

$y = 1 - \frac{x^{2}}{3}$

Step 3

To rewrite as a function of $x$ , write the equation so that $y$ is by itself on one side of the equal sign and an expression involving only $x$ is on the other side.

$f (x) = 1 - \frac{x^{2}}{3}$

Write as a Function of x x^2+3y=3

Related Questions

Support LCMGCF.com by disabling your adblocker.