Write as a Set of Linear Factors 9x^2+11x+4=2

$9 x^{2} + 11 x + 4 = 2$

Step 1

Subtract $2$ from both sides of the equation.

$9 x^{2} + 11 x + 4 - 2 = 0$

Step 2

Subtract $2$ from $4$ .

$9 x^{2} + 11 x + 2 = 0$

Step 3

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 9 \cdot 2 = 18$ and whose sum is $b = 11$ .

Factor $11$ out of $11 x$ .

$9 x^{2} + 11 (x) + 2 = 0$

Rewrite $11$ as $2$ plus $9$

$9 x^{2} + (2 + 9) x + 2 = 0$

Apply the distributive property.

$9 x^{2} + 2 x + 9 x + 2 = 0$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(9 x^{2} + 2 x) + 9 x + 2 = 0$

Factor out the greatest common factor (GCF) from each group.

$x (9 x + 2) + 1 (9 x + 2) = 0$

Factor the polynomial by factoring out the greatest common factor, $9 x + 2$ .

$(9 x + 2) (x + 1) = 0$

Write as a Set of Linear Factors 9x^2+11x+4=2

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