Write in Exponential Form -3 = log base 2 of 1/8

$- 3 = \log_{2} (\frac{1}{8})$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 2$ , $x = \frac{1}{8}$ , and $y = - 3$ .