Write in Exponential Form log base 17 of 289=2

$\log_{17} (289) = 2$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 17$ , $x = 289$ , and $y = 2$ .

$b = 17$