Write in Exponential Form log base 5 of 2x=1/6

$\log_{5} (2 x) = \frac{1}{6}$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 5$ , $x = 2 x$ , and $y = \frac{1}{6}$ .

$b = 5$

$x = 2 x$

$y = \frac{1}{6}$

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

$5^{\frac{1}{6}} = 2 x$

Write in Exponential Form log base 5 of 2x=1/6

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