Write in Exponential Form log base 2 of cube root of 2=1/3

$\log_{2} (\sqrt[3]{2}) = \frac{1}{3}$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 2$ , $x = \sqrt[3]{2}$ , and $y = \frac{1}{3}$ .

$b = 2$

$x = \sqrt[3]{2}$

$y = \frac{1}{3}$

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

$2^{\frac{1}{3}} = \sqrt[3]{2}$

Write in Exponential Form log base 2 of cube root of 2=1/3

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