Write in Exponential Form log base 3 of 1/3=-1

$\log_{3} (\frac{1}{3}) = - 1$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 3$ , $x = \frac{1}{3}$ , and $y = - 1$ .

$b = 3$

$x = \frac{1}{3}$

$y = - 1$

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

$3^{- 1} = \frac{1}{3}$

Write in Exponential Form log base 3 of 1/3=-1

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