Write in Exponential Form log base 8 of 1/64=-2

$\log_{8} (\frac{1}{64}) = - 2$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 8$ , $x = \frac{1}{64}$ , and $y = - 2$ .