Write in Exponential Form log base 3 of 1/81=-4

$\log_{3} (\frac{1}{81}) = - 4$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 3$ , $x = \frac{1}{81}$ , and $y = - 4$ .

$b = 3$

$x = \frac{1}{81}$

$y = - 4$

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

$3^{- 4} = \frac{1}{81}$

Write in Exponential Form log base 3 of 1/81=-4

Related Questions

Support LCMGCF.com by disabling your adblocker.