Write in Exponential Form log base 4 of 1/64=-3

$\log_{4} (\frac{1}{64}) = - 3$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 4$ , $x = \frac{1}{64}$ , and $y = - 3$ .

$b = 4$

$x = \frac{1}{64}$

$y = - 3$

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

$4^{- 3} = \frac{1}{64}$

Write in Exponential Form log base 4 of 1/64=-3

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