Write in Standard Form (3x-8)(x+2)=2x^2

$(3 x - 8) (x + 2) = 2 x^{2}$

Step 1

Subtract $2 x^{2}$ from both sides of the equation.

$(3 x - 8) (x + 2) - 2 x^{2} = 0$

Step 2

Simplify $(3 x - 8) (x + 2) - 2 x^{2}$ .

Simplify each term.

Expand $(3 x - 8) (x + 2)$ using the FOIL Method.

Apply the distributive property.

$3 x (x + 2) - 8 (x + 2) - 2 x^{2} = 0$

Apply the distributive property.

$3 x \cdot x + 3 x \cdot 2 - 8 (x + 2) - 2 x^{2} = 0$

Apply the distributive property.

$3 x \cdot x + 3 x \cdot 2 - 8 x - 8 \cdot 2 - 2 x^{2} = 0$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ by adding the exponents.

Move $x$ .

$3 (x \cdot x) + 3 x \cdot 2 - 8 x - 8 \cdot 2 - 2 x^{2} = 0$

Multiply $x$ by $x$ .

$3 x^{2} + 3 x \cdot 2 - 8 x - 8 \cdot 2 - 2 x^{2} = 0$

Multiply $2$ by $3$ .

$3 x^{2} + 6 x - 8 x - 8 \cdot 2 - 2 x^{2} = 0$

Multiply $- 8$ by $2$ .

$3 x^{2} + 6 x - 8 x - 16 - 2 x^{2} = 0$

Subtract $8 x$ from $6 x$ .

$3 x^{2} - 2 x - 16 - 2 x^{2} = 0$

Subtract $2 x^{2}$ from $3 x^{2}$ .

$x^{2} - 2 x - 16 = 0$

Step 3

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Step 4

The standard form is $x^{2} - 2 x - 16$ .

$x^{2} - 2 x - 16 = 0$

Step 5