Write in Exponential Form log base 7 of 7=1

$\log_{7} (7) = 1$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 7$ , $x = 7$ , and $y = 1$ .

$b = 7$