Write in Exponential Form log base 7 of x^2-2x-11=3x

$\log_{7} (x^{2} - 2 x - 11) = 3 x$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 7$ , $x = x^{2} - 2 x - 11$ , and $y = 3 x$ .

$b = 7$

$x = x^{2} - 2 x - 11$

$y = 3 x$

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

$7^{3 x} = x^{2} - 2 x - 11$

Write in Exponential Form log base 7 of x^2-2x-11=3x

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