Write in Exponential Form log base (x-4) of 4=3/2

$\log_{(x - 4)} (4) = \frac{3}{2}$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = x - 4$ , $x = 4$ , and $y = \frac{3}{2}$ .

$b = x - 4$

$x = 4$

$y = \frac{3}{2}$

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

${(x - 4)}^{\frac{3}{2}} = 4$

Write in Exponential Form log base (x-4) of 4=3/2

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