Write in Exponential Form log base (x+4) of x^2-3x-5=3/4

$\log_{(x + 4)} (x^{2} - 3 x - 5) = \frac{3}{4}$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = x + 4$ , $x = x^{2} - 3 x - 5$ , and $y = \frac{3}{4}$ .

$b = x + 4$

$x = x^{2} - 3 x - 5$

$y = \frac{3}{4}$

Step 2

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

${(x + 4)}^{\frac{3}{4}} = x^{2} - 3 x - 5$

Write in Exponential Form log base (x+4) of x^2-3x-5=3/4

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