Write in Exponential Form natural log of 4x+1=3/7

$\ln (4 x + 1) = \frac{3}{7}$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = e$ , $x = 4 x + 1$ , and $y = \frac{3}{7}$ .