Write in Exponential Form natural log of x^2-x+17=3/4

$\ln (x^{2} - x + 17) = \frac{3}{4}$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = e$ , $x = x^{2} - x + 17$ , and $y = \frac{3}{4}$ .

$b = e$

$x = x^{2} - x + 17$

$y = \frac{3}{4}$

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

$e^{\frac{3}{4}} = x^{2} - x + 17$

Write in Exponential Form natural log of x^2-x+17=3/4

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