Write in Slope-Intercept Form (1,3) and (-3,-5)

$(1, 3)$ and $(- 3, - 5)$

Step 1

Find the slope of the line between $(1, 3)$ and $(- 3, - 5)$ using $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ , which is the change of $y$ over the change of $x$ .

Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{change in y}{change in x}$

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{- 5 - (3)}{- 3 - (1)}$

Simplify.

Simplify the numerator.

Multiply $- 1$ by $3$ .

$m = \frac{- 5 - 3}{- 3 - (1)}$

Subtract $3$ from $- 5$ .

$m = \frac{- 8}{- 3 - (1)}$

Simplify the denominator.

Multiply $- 1$ by $1$ .

$m = \frac{- 8}{- 3 - 1}$

Subtract $1$ from $- 3$ .

$m = \frac{- 8}{- 4}$

Divide $- 8$ by $- 4$ .

$m = 2$

Step 2

Use the slope $2$ and a given point $(1, 3)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (3) = 2 \cdot (x - (1))$

Step 3

Simplify the equation and keep it in point-slope form.

$y - 3 = 2 \cdot (x - 1)$

Step 4

Solve for $y$ .

Simplify $2 \cdot (x - 1)$ .

Rewrite.

$y - 3 = 0 + 0 + 2 \cdot (x - 1)$

Simplify by adding zeros.

$y - 3 = 2 \cdot (x - 1)$

Apply the distributive property.

$y - 3 = 2 x + 2 \cdot - 1$

Multiply $2$ by $- 1$ .

$y - 3 = 2 x - 2$

Move all terms not containing $y$ to the right side of the equation.

Add $3$ to both sides of the equation.

$y = 2 x - 2 + 3$

Add $- 2$ and $3$ .

$y = 2 x + 1$

Step 5

Write in Slope-Intercept Form (1,3) and (-3,-5)

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