Write in Standard Form 3(x^2-2x+4)=0

$3 (x^{2} - 2 x + 4) = 0$

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Apply the distributive property.

$3 x^{2} + 3 (- 2 x) + 3 \cdot 4 = 0$

Simplify.

Multiply $- 2$ by $3$ .

$3 x^{2} - 6 x + 3 \cdot 4 = 0$

Multiply $3$ by $4$ .

$3 x^{2} - 6 x + 12 = 0$