Write in Slope-Intercept Form (-2,4) and (3,-1)

$(- 2, 4)$ and $(3, - 1)$

Step 1

Find the slope of the line between $(- 2, 4)$ and $(3, - 1)$ using $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ , which is the change of $y$ over the change of $x$ .

Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{change in y}{change in x}$

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{- 1 - (4)}{3 - (- 2)}$

Simplify.

Simplify the numerator.

Multiply $- 1$ by $4$ .

$m = \frac{- 1 - 4}{3 - (- 2)}$

Subtract $4$ from $- 1$ .

$m = \frac{- 5}{3 - (- 2)}$

Simplify the denominator.

Multiply $- 1$ by $- 2$ .

$m = \frac{- 5}{3 + 2}$

Add $3$ and $2$ .

$m = \frac{- 5}{5}$

Divide $- 5$ by $5$ .

$m = - 1$

Step 2

Use the slope $- 1$ and a given point $(- 2, 4)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (4) = - 1 \cdot (x - (- 2))$

Step 3

Simplify the equation and keep it in point-slope form.

$y - 4 = - 1 \cdot (x + 2)$

Step 4

Solve for $y$ .

Simplify $- 1 \cdot (x + 2)$ .

Rewrite.

$y - 4 = 0 + 0 - 1 \cdot (x + 2)$

Simplify by adding zeros.

$y - 4 = - 1 \cdot (x + 2)$

Apply the distributive property.

$y - 4 = - 1 x - 1 \cdot 2$

Simplify the expression.

Rewrite $- 1 x$ as $- x$ .

$y - 4 = - x - 1 \cdot 2$

Multiply $- 1$ by $2$ .

$y - 4 = - x - 2$

Move all terms not containing $y$ to the right side of the equation.

Add $4$ to both sides of the equation.

$y = - x - 2 + 4$

Add $- 2$ and $4$ .

$y = - x + 2$

Step 5

Write in Slope-Intercept Form (-2,4) and (3,-1)

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